CA Foundation Exam > CA Foundation Questions > {(x , y), y=x2} isa)not a functionb)a functio...
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{(x , y), y=x2} is
- a)not a function
- b)a function
- c)inverse mapping
- d)none of these
Correct answer is option 'B'. Can you explain this answer?
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{(x , y), y=x2} isa)not a functionb)a functionc)inverse mappingd)none ...
Explanation:
This question is asking about whether the given set of ordered pairs {(x, y), y = x²} represents a function or not.
- Definition of a Function: A function is a set of ordered pairs in which no two different ordered pairs have the same first element (also known as the input or domain value).
- Testing for a Function: To test whether a set of ordered pairs represents a function, we need to check whether there are any two different ordered pairs with the same first element. If there are, then the set does not represent a function.
In the given set of ordered pairs {(x, y), y = x²}, the y-value is defined in terms of the x-value using the equation y = x². This means that for every possible value of x, there is only one corresponding value of y. Therefore, there cannot be any two different ordered pairs with the same first element, and the set represents a function.
Answer: Option (B) - a function.
This question is asking about whether the given set of ordered pairs {(x, y), y = x²} represents a function or not.
- Definition of a Function: A function is a set of ordered pairs in which no two different ordered pairs have the same first element (also known as the input or domain value).
- Testing for a Function: To test whether a set of ordered pairs represents a function, we need to check whether there are any two different ordered pairs with the same first element. If there are, then the set does not represent a function.
In the given set of ordered pairs {(x, y), y = x²}, the y-value is defined in terms of the x-value using the equation y = x². This means that for every possible value of x, there is only one corresponding value of y. Therefore, there cannot be any two different ordered pairs with the same first element, and the set represents a function.
Answer: Option (B) - a function.
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{(x , y), y=x2} isa)not a functionb)a functionc)inverse mappingd)none ...
It is function because for all real values of x u get differwnt squares
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{(x , y), y=x2} isa)not a functionb)a functionc)inverse mappingd)none of theseCorrect answer is option 'B'. Can you explain this answer?
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